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x+z=1, x+2z=4

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x+z=1, x+2z=4

Solution

x=−2, z=3

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Solve by:

Solve by substitution

Solve by elimination

Solve by Cramer's rule

Solve by Gaussian elimination

One step at a time

[

x+z=1

x+2z=4

]

Isolate x for x+z=1: x=1−z

Substitute x=1−z

[

1−z+2z=4

]

Simplify

[

1+z=4

]

Isolate z for 1+z=4: z=3

For x=1−z

Substitute z=3

x=1−3

Simplify

x=−2

The solutions to the system of equations are:

x=−2, z=3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

x+z=1, x+2z=4

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