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inverse of f(x)=cos(2x+5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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inverse f(x)=cos(2x+5)

Solution

arccos(x)−52

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Function Inverse definition

A function g is the inverse of function f if for y=f(x), x=g(y)

cos(a)=b ⇒ a=arccos(b)

2x+5=arccos(y)

Solve for x, 2x+5=arccos(y)

arccos(y)−52

Substitute y=x

arccos(x)−52

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domain cos(2x+5)

range cos(2x+5)

periodicity cos(2x+5)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of f(x)=cos(2x+5)

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