y^{\prime}cos(x)=ysin(x)+sin(2x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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x²+4x−5=0

Solution

x=1, x=−5

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Solve by:

Quadratic formula

Completing the square

Factoring method

One step at a time

−r²−r+2=0

Solve with the quadratic formula

r_{1, 2}=−(−1)± √(−1)²−4(−1)· 22(−1)

√(−1)²−4(−1)· 2=3

r_{1, 2}=−(−1)± 32(−1)

Separate the solutions

r₁=−(−1)+32(−1) , r₂=−(−1)−32(−1)

r=−(−1)+32(−1) : −2

r=−(−1)−32(−1) : 1

The solutions to the quadratic equation are:

r=−2, r=1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

y^{\prime}cos(x)=ysin(x)+sin(2x)

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