x+y=2, y=x^2-18

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify solve for inverse tangent line

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x+y=2, y=x²−18

Solution

(

`x`=−5,	`y`=7
`x`=4,	`y`=−2

)

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Solution steps

One step at a time

[

x+y=2

y=x²−18

]

Subtract the equations

x+y=2

−

y=x²−18

x+y−y=2−(x²−18)

Simplify

x=−x²+20

Solve x=−x²+20: x=−5, x=4

Plug the solutions x=−5, x=4 into x+y=2

For x+y=2, subsitute x with −5: y=7

For x+y=2, subsitute x with 4: y=−2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for x+y=2, y=x²−18 are

(

`x`=−5,	`y`=7
`x`=4,	`y`=−2

)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

x+y=2, y=x^2-18

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