vertex x^2+4

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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simplify (9x⁴+8x)−(−2x⁴−4x+5)

Solution

11x⁴+12x−5

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Solution steps

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(9x⁴+8x)−(−2x⁴−4x+5)

Apply rule: (a)=a

(9x⁴+8x)=9x⁴+8x

=9x⁴+8x−(−2x⁴−4x+5)

Apply the distributive law: −(−a−b)=a+b

−(−2x⁴−4x+5)=2x⁴+4x−5

=9x⁴+8x+2x⁴+4x−5

Group like terms

=9x⁴+2x⁴+8x+4x−5

Add similar elements: 9x⁴+2x⁴=11x⁴

=11x⁴+8x+4x−5

Add similar elements: 8x+4x=12x

=11x⁴+12x−5

Solve instead

f(x)=(9x⁴+8x)−(−2x⁴−4x+5)

ddx ((9x⁴+8x)−(−2x⁴−4x+5))

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertex x^2+4

Solution

Solution steps

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