solve by quadratic formula 1/4 x^2-1/32 x-7/32 =0

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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domain 1x²

Solution

x<0 or x>0

Interval Notation

(−∞ , 0)∪(0, ∞ )

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Domain definition

The domain of a function is the set of input or argument values for which the function is real and defined

Find undefined (singularity) points: x=0

The function domain

x<0 or x>0

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range 1x²

inverse 1x²

intercepts 1x²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

solve by quadratic formula 1/4 x^2-1/32 x-7/32 =0

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