parity 2x^2-5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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parity 2x²−5

Solution

Even

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Parity Definition

Even Function: A function is even if f(−x)=f(x) for all x∈ℝ
Odd Function: A function is odd if f(−x)=−f(x) for all x∈ℝ

f(−x): 2x²−5

−f(x): −2x²+5

Check parity of 2x²−5

Check if Even: True

Check if Odd: False

Even

Solve instead

domain 2x²−5

range 2x²−5

vertices 2x²−5

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

parity 2x^2-5

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