g(x)=x-2, h(x)=3x-4, (h+g)(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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g(x)=x−2, h(x)=3x−4, (h(x)+g(x))(x)

Solution

4x−6

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Find (h+g)(x) given g(x)=x−2, h(x)=3x−4

(h+g)(x)=h(x)+g(x)

h(x)=3x−4

g(x)=x−2

=3x−4+x−2

Simplify 3x−4+x−2: 4x−6

=4x−6

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

g(x)=x-2, h(x)=3x-4, (h+g)(x)

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