factor 4x^2-4x+1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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factor 4x²−4x+1

Solution

(2x−1)²

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Solution steps

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4x²−4x+1

Rewrite in the form of a²+2ab+b²:

4x²=(2x)²

1=1²

−4x=−2· 2x· 1

=(2x)²−2· 2x· 1+1²

Apply Perfect Square Formula: a²−2ab+b²=(a−b)²

(2x)²−2· 2x· 1+1²=(2x−1)²

=(2x−1)²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

factor 4x^2-4x+1

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