factor (5x+2)^2-(2y-5)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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x²+2x−3=0

Solution

x=1, x=−3

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Solve by:

Completing the square

Quadratic formula

Factoring method

One step at a time

x²+2x−3=0

Move 3 to the right side

x²+2x=3

Rewrite in the form (x+a)²=b

(x+1)²=4

For f ²(x)=a the solutions are f(x)=√a, −√a

Solve x+1=√4: x=1

Solve x+1=−√4: x=−3

The solutions to the quadratic equation are:

x=1, x=−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

factor (5x+2)^2-(2y-5)^2

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