convergence sum from n=1 to infinity}(-1)^{n+1 of 2^{1/n}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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simplify 4⁻¹¹4⁻⁸

Solution

164

Decimal

0.015625

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Solution steps

One step at a time

4⁻¹¹4⁻⁸

Apply exponent rule: x^ax^b =x^a−b

=4^{−11−(−8)}

Apply rule −(−a)=a

=4⁻¹¹⁺⁸

Add/Subtract the numbers: −11+8=−3

=4⁻³

Apply exponent rule: a^−b=1a^b

=14³

4³=64

=164

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

convergence sum from n=1 to infinity}(-1)^{n+1 of 2^{1/n}

Solution

Solution steps

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