11+4+3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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xy=10, 2x+y=1

Solution

(

`x`=14 −`i`√794 ,	`y`=12 +`i`√792
`x`=14 +`i`√794 ,	`y`=12 −`i`√792

)

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Solution steps

One step at a time

[

xy=10

2x+y=1

]

Isolate x for xy=10: x=10y ; y≠ 0

Plug the solutions x=10y into 2x+y=1

For 2x+y=1, subsitute x with 10y : y=12 +i√792 , y=12 −i√792

Plug the solutions y=12 +i√792 , y=12 −i√792 into xy=10

For xy=10, subsitute y with 12 +i√792 : x=14 −i√794

For xy=10, subsitute y with 12 −i√792 : x=14 +i√794

Verify solutions by plugging them into the original equations

Therefore, the final solutions for xy=10, 2x+y=1 are

(

`x`=14 −`i`√794 ,	`y`=12 +`i`√792
`x`=14 +`i`√794 ,	`y`=12 −`i`√792

)

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

11+4+3

Solution

Solution steps

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