integral of sin(3x+4)

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∫ sin(3x+4)dx

Solution

−13 cos(3x+4)+C

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Solution steps

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∫ sin(3x+4)dx

Apply u-substitution: ∫ sin(u)13 du

=∫ sin(u)13 du

Take the constant out: ∫a·f(x)dx=a·∫f(x)dx

=13 · ∫ sin(u)du

Use the common integral: ∫ sin(u)du=−cos(u)

=13 (−cos(u))

Substitute back u=3x+4

=13 (−cos(3x+4))

Simplify

=−13 cos(3x+4)

Add a constant to the solution

=−13 cos(3x+4)+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of sin(3x+4)

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