integral of (x+1)sin(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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∫ (x+1)sin(x)dx

Solution

−cos(x)(x+1)+sin(x)+C

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∫ (x+1)sin(x)dx

Apply Integration By Parts: −cos(x)(x+1)−∫ −cos(x)dx

=−cos(x)(x+1)−∫ −cos(x)dx

∫ −cos(x)dx=−sin(x)

=−cos(x)(x+1)−(−sin(x))

Simplify

=−cos(x)(x+1)+sin(x)

Add a constant to the solution

=−cos(x)(x+1)+sin(x)+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of (x+1)sin(x)

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