derivative of (x^2-x/2)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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ddx (x²−x2 )

Solution

x−12

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ddx (x²−x2 )

Take the constant out: (a·f)′=a·f ′

=12 ddx (x²−x)

Apply the Sum/Difference Rule: (f±g)′=f ′±g′

=12 (ddx (x²)−dxdx )

ddx (x²)=2x

dxdx =1

=12 (2x−1)

Simplify 12 (2x−1): x−12

=x−12

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (x^2-x/2)

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