derivative of (3x^2+5x+4/(sqrt(x)))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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ddx (3x²+5x+4√x )

Solution

9x²+5x−42x√x

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ddx (3x²+5x+4√x )

Apply the Quotient Rule: (fg )^′=f ′·g−g′·fg²

=ddx (3x²+5x+4)√x−ddx (√x)(3x²+5x+4)(√x)²

ddx (3x²+5x+4)=6x+5

ddx (√x)=12√x

=(6x+5)√x−12√x (3x²+5x+4)(√x)²

Simplify (6x+5)√x−12√x (3x²+5x+4)(√x)² : 9x²+5x−42x√x

=9x²+5x−42x√x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (3x^2+5x+4/(sqrt(x)))

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