derivative of (sin(x)/(2x))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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simplify solve for inverse tangent line

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ddx (sin(x)2x )

Solution

xcos(x)−sin(x)2x²

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ddx (sin(x)2x )

Take the constant out: (a·f)′=a·f ′

=12 ddx (sin(x)x )

Apply the Quotient Rule: (fg )^′=f ′·g−g′·fg²

=12 · ddx (sin(x))x−dxdx sin(x)x²

ddx (sin(x))=cos(x)

dxdx =1

=12 · cos(x)x−1· sin(x)x²

Simplify 12 · cos(x)x−1· sin(x)x² : xcos(x)−sin(x)2x²

=xcos(x)−sin(x)2x²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (sin(x)/(2x))

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