8/(3x-2)= 2/(x-1)

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(x+y)x² =6, x=8−y

Solution

(

`x`=2√3 ,	`y`=8−2√3
`x`=−2√3 ,	`y`=8+2√3

)

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Solution steps

One step at a time

[

(x+y)x² =6

x=8−y

]

Isolate y for x=8−y: y=8−x

Plug the solutions y=8−x into (x+y)x² =6

For (x+y)x² =6, subsitute y with 8−x: x=2√3 , x=−2√3

Plug the solutions x=2√3 , x=−2√3 into x=8−y

For x=8−y, subsitute x with 2√3 : y=8−2√3

For x=8−y, subsitute x with −2√3 : y=8+2√3

Verify solutions by plugging them into the original equations

Therefore, the final solutions for (x+y)x² =6, x=8−y are

(

`x`=2√3 ,	`y`=8−2√3
`x`=−2√3 ,	`y`=8+2√3

)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

8/(3x-2)= 2/(x-1)

Solution

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