(6a^2+5a+10)-(4a^2+6a+12)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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simplify (6a²+5a+10)−(4a²+6a+12)

Solution

2a²−a−2

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Solution steps

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(6a²+5a+10)−(4a²+6a+12)

Apply rule: (a)=a

(6a²+5a+10)=6a²+5a+10

=6a²+5a+10−(4a²+6a+12)

Apply the distributive law: −(a+b)=−a−b

−(4a²+6a+12)=−4a²−6a−12

=6a²+5a+10−4a²−6a−12

Group like terms

=6a²−4a²+5a−6a+10−12

Add similar elements: 6a²−4a²=2a²

=2a²+5a−6a+10−12

Add similar elements: 5a−6a=−a

=2a²−a+10−12

Subtract the numbers: 10−12=−2

=2a²−a−2

Solve instead

f(a)=(6a²+5a+10)−(4a²+6a+12)

dda ((6a²+5a+10)−(4a²+6a+12))

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(6a^2+5a+10)-(4a^2+6a+12)

Solution

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