(3x^2+4xy)dx+(2x^2+2y)dy=0

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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lim_{x→ ∞}(5x³+1x²−4 )

Solution

∞

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lim_{x→ ∞}(5x³+1x²−4 )

Divide by highest denominator power: 5x+1x² 1−4x²

=lim_{x→ ∞}(5x+1x² 1−4x² )

lim_x→a[f(x)g(x) ]=lim_x→af(x)lim_x→ag(x) , lim_x→ag(x)≠0
With the exception of indeterminate form

=lim_{x→ ∞}(5x+1x² )lim_{x→ ∞}(1−4x² )

lim_{x→ ∞}(5x+1x² )=∞

lim_{x→ ∞}(1−4x² )=1

=∞ 1

Apply Infinity Property: ∞c =∞

=∞

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(3x^2+4xy)dx+(2x^2+2y)dy=0

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