(log_{b}(5))(log_{5}(b))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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simplify (log_b(5))(log₅(b))

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(log_b(5))(log₅(b))

Simplify (log_b(5))(log₅(b)): log_b(5)log₅(b)

=log_b(5)log₅(b)

Apply log rule: log_a(b)=log_c(b)log_c(a)

log_b(5)=ln(5)ln(b)

=ln(5)ln(b) log₅(b)

Apply log rule: log_a(b)=log_c(b)log_c(a)

log₅(b)=ln(b)ln(5)

=ln(5)ln(b) · ln(b)ln(5)

Cross cancel: ab ·ba =1

Solve instead

f(b)=(log_b(5))(log₅(b))

ddb ((log_b(5))(log₅(b)))

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(log_{b}(5))(log_{5}(b))

Solution

Solution steps

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