((-13)×(-30))\div((30+16+11+21)\div(-3))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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((−13)× (−30))÷ ((30+16+11+21)÷ (−3))

Solution

−15

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Solution steps

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((−13)× (−30))÷ ((30+16+11+21)÷ (−3))

Follow the PEMDAS order of operations

Calculate within parentheses ((−13)× (−30)) : 390

=390÷ ((30+16+11+21)÷ (−3))

Calculate within parentheses ((30+16+11+21)÷ (−3)) : −26

=390÷ (−26)

Multiply and divide (left to right) 390÷ (−26) : −15

=−15

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

((-13)×(-30))\div((30+16+11+21)\div(-3))

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