f(x)=(7x^2+6)+(2x^2-4)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify solve for inverse tangent line

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f(x)=(7x²+6)+(2x²−4)

Solution

Domain: −∞ <x<∞

Range: f(x)≥ 2

Y Intercepts: (0, 2)

Vertex: Minimum (0, 2)

Inverse: √x−23 , −√x−23

Interval Notation

Domain: (−∞ , ∞ )

Range: [2, ∞ )

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Domain of 7x²+6+2x²−4 : −∞ <x<∞

Range of 7x²+6+2x²−4: f(x)≥ 2

Axis interception points of 7x²+6+2x²−4: Y Intercepts: (0, 2)

Vertex of 7x²+6+2x²−4: Minimum (0, 2)

Inverse of 7x²+6+2x²−4: √x−23 , −√x−23

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ddx ((7x²+6)+(2x²−4))

parity 7x²+6+2x²−4

symmetry 7x²+6+2x²−4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

f(x)=(7x^2+6)+(2x^2-4)

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