derivative of (7x^2+6+(2x^2-4))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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∫₀^2π∫₁^√2∫_r^2−r²(2−2r²)rdzdrdθ

Solution

π(3+8√2)15

Decimal

2.99785…

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Solution steps

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∫₀^2π∫₁^√2∫_r^2−r²(2−2r²)rdzdrdθ

∫_r^2−r²(2−2r²)rdz=(2−2r²)r(2−r²)−r²(2−2r²)

=∫₀^2π∫₁^√2((2−2r²)r(2−r²)−r²(2−2r²))drdθ

∫₁^√2((2−2r²)r(2−r²)−r²(2−2r²))dr=−16 +4√2+415

=∫₀^2π(−16 +4√2+415 )dθ

∫₀^2π(−16 +4√2+415 )dθ=π(3+8√2)15

=π(3+8√2)15

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (7x^2+6+(2x^2-4))

Solution

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