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laplace transform cos(2x+5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inverse (

1	2	3
4	6	9
3	7	1

)

Solution

(

−3	1	0
2319	−819	319
1019	−119	−219

)

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lim_{x→ ∞}(x³−4x−10x²−x−6 )

Divide by highest denominator power: x−4x −10x² 1−1x −6x²

=lim_{x→ ∞}(x−4x −10x² 1−1x −6x² )

lim_x→a[f(x)g(x) ]=lim_x→af(x)lim_x→ag(x) , lim_x→ag(x)≠0
With the exception of indeterminate form

=lim_{x→ ∞}(x−4x −10x² )lim_{x→ ∞}(1−1x −6x² )

lim_{x→ ∞}(x−4x −10x² )=∞

lim_{x→ ∞}(1−1x −6x² )=1

=∞ 1

Apply Infinity Property: ∞c =∞

=∞

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1	2	3
4	6	9
3	7	1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

laplace transform cos(2x+5)

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