vertices 2|x|-1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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vertices 2|x|−1

Solution

(0, −1)

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Solution steps

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Absolute value function vertex definition

Absolute value function vertex points are points where absolute values are zeros

Find the absolute values zeroes:

Solve |x|=0: x=0

x=0

Plug in x=0 to find the y value: (0, −1)

Therefore absolute value function vertices are

(0, −1)

Solve instead

domain 2|x|−1

range 2|x|−1

intercepts 2|x|−1

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