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Vector Scalar Projection Calculator

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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domain √x²+1

Solution

−∞ <x<∞

Interval Notation

(−∞ , ∞ )

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Solution steps

One step at a time

(

3	−5
−2	8

)

Matrix eigenvectors

Let A be a square matrix, η a vector and λ a scalar that satisfy Aη=λη,
then η is an eigenvector of A and λ is the eigenvalue associated with it

To find the eigenvectors η, solve (A−λ I)η=0 for each eigenvalue λ

Find the eigenvalues for (

3	−5
−2	8

): λ=11+√652 , λ=11−√652

Eigenvectors for λ=11+√652 : (

5−√65

)

Eigenvectors for λ=11−√652 : (

√65+5

)

The eigenvectors for (

3	−5
−2	8

)

5−√65

), (

√65+5

)

Solve instead

range √x²+1

inverse √x²+1

intercepts √x²+1

Vector Scalar Projection Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

Vector Scalar Projection Calculator

Solution

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