prove cos^2(x)-sin^2(x)=2cos^2(x)-1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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√☐

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log_□

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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prove cos²(x)−sin²(x)=2cos²(x)−1

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True

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cos²(x)−sin²(x)=2cos²(x)−1

Manipulating left side

cos²(x)−sin²(x)

Rewrite using trig identities

=2cos²(x)−1

We showed that the two sides could take the same form

⇒ True

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+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
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prove cos^2(x)-sin^2(x)=2cos^2(x)-1

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