inverse of -2|x|-1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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ddx (x³4−x² )

Solution

12x²−x⁴(4−x²)²

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ddx (x³4−x² )

Apply the Quotient Rule: (fg )^′=f ′·g−g′·fg²

=ddx (x³)(4−x²)−ddx (4−x²)x³(4−x²)²

ddx (x³)=3x²

ddx (4−x²)=−2x

=3x²(4−x²)−(−2x)x³(4−x²)²

Simplify 3x²(4−x²)−(−2x)x³(4−x²)² : 12x²−x⁴(4−x²)²

=12x²−x⁴(4−x²)²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of -2|x|-1

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