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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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inverse 1x² +1x

Solution

1+√1+4x2x , 1−√1+4x2x

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Function Inverse definition

A function g is the inverse of function f if for y=f(x), x=g(y)

y=1x² +1x

Replace x with y

x=1y² +1y

Solve for y, x=1y² +1y

1+√1+4x2x , 1−√1+4x2x

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domain 1x² +1x

range 1x² +1x

intercepts 1x² +1x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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