expand (4a-2b)^3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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expand (4a−2b)³

Solution

64a³−96a²b+48ab²−8b³

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(4a−2b)³

Apply Perfect Cube Formula: (a−b)³=a³−3a²b+3ab²−b³

(4a−2b)³=(4a)³−3(4a)²· 2b+3· 4a(2b)²−(2b)³

=(4a)³−3(4a)²· 2b+3· 4a(2b)²−(2b)³

Simplify (4a)³−3(4a)²· 2b+3· 4a(2b)²−(2b)³: 64a³−96a²b+48ab²−8b³

=64a³−96a²b+48ab²−8b³

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

expand (4a-2b)^3

Solution

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