5+4x+2>= x+8-1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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5+4x+2≥ x+8−1

Solution

x≥ 0

Interval Notation

[0, ∞ )

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Solution steps

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5+4x+2≥ x+8−1

Group like terms

4x+5+2≥ x+8−1

Add the numbers: 5+2=7

4x+7≥ x+8−1

Add/Subtract the numbers: 8−1=7

4x+7≥ x+7

Move 7 to the right side

4x≥ x

Move x to the left side

3x≥ 0

Divide both sides by 3

x≥ 0

Number Line

x≥ 0

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

5+4x+2>= x+8-1

Solution

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