derivative of (x+1cos(x))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx ((x+1)cos(x))

Solution

cos(x)−sin(x)(x+1)

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ddx ((x+1)cos(x))

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=x+1, g=cos(x)

=ddx (x+1)cos(x)+ddx (cos(x))(x+1)

ddx (x+1)=1

ddx (cos(x))=−sin(x)

=1· cos(x)+(−sin(x))(x+1)

Simplify

=cos(x)−sin(x)(x+1)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (x+1cos(x))

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