d/(da)(a^2(5a^3)(a^6))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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dda (a²(5a³)(a⁶))

Solution

55a¹⁰

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dda (a²(5a³)(a⁶))

Take the constant out: (a·f)′=a·f ′

=5dda (a²a³a⁶)

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=a², g=a³a⁶

=5(dda (a²)a³a⁶+dda (a³a⁶)a²)

dda (a²)=2a

dda (a³a⁶)=9a⁸

=5(2aa³a⁶+9a⁸a²)

Simplify 5(2aa³a⁶+9a⁸a²): 55a¹⁰

=55a¹⁰

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

d/(da)(a^2(5a^3)(a^6))

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