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row echelon (

3	−5
−2	8

)

Solution

(

3	−5
0	143

)

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(

3	−5
−2	8

)

Matrix eigenvectors

Let A be a square matrix, η a vector and λ a scalar that satisfy Aη=λη,
then η is an eigenvector of A and λ is the eigenvalue associated with it

To find the eigenvectors η, solve (A−λ I)η=0 for each eigenvalue λ

Find the eigenvalues for (

3	−5
−2	8

): λ=11+√652 , λ=11−√652

Eigenvectors for λ=11+√652 : (

5−√65

)

Eigenvectors for λ=11−√652 : (

√65+5

)

The eigenvectors for (

3	−5
−2	8

)

5−√65

), (

√65+5

)

Matrix Transpose Examples

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3	−5
−2	8

) or choose below

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

`a`	1
`a`	`b`

Matrix Transpose Calculator

Solution

Solution steps

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