Matrix Inverse Calculator - Free Online Calculator With Steps & Examples

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx ((x²+2x−1)· (2x²−3x+6))

Solution

8x³+3x²−4x+15

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ddx ((x²+2x−1)(2x²−3x+6))

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=x²+2x−1, g=2x²−3x+6

=ddx (x²+2x−1)(2x²−3x+6)+ddx (2x²−3x+6)(x²+2x−1)

ddx (x²+2x−1)=2x+2

ddx (2x²−3x+6)=4x−3

=(2x+2)(2x²−3x+6)+(4x−3)(x²+2x−1)

Simplify (2x+2)(2x²−3x+6)+(4x−3)(x²+2x−1): 8x³+3x²−4x+15

=8x³+3x²−4x+15

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

Matrix Inverse Calculator - Free Online Calculator With Steps & Examples

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