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∫2−√x4−xdx
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Solution
−4(12ln|√x2+1|−12ln|√x2−1|−12√x)−2ln|x−4|+C
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Solution steps
Solve by:
One step at a time
tan(x)−cot(x)tan(x)+cot(x)=2sin2(x)−1
Manipulating left side
tan(x)−cot(x)tan(x)+cot(x)
Express with sin, cos
=−cos2(x)+sin2(x)cos2(x)+sin2(x)
Rewrite using trig identities
=−1+2sin2(x)
=2sin2(x)−1
We showed that the two sides could take the same form