Matrix Adjoint Calculator

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eigenvalues (

1	−4
4	−7

)

Solution

λ=−3 with multiplicity of 2

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Solution steps

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(

1	−4
4	−7

)

Matrix eigenvalues

Let A be a square matrix, η a vector and λ a scalar that satisfy Aη=λη,
then λ is called the eigenvalue associated with the eigenvector η of A

The eigenvalues of A are the roots of the characteristic equation det(A−λ I)=0

det((

1	−4
4	−7

)−λ(

1	0
0	1

)): λ²+6λ+9

Solve λ²+6λ+9=0: λ=−3 with multiplicity of 2

The eigenvalues are:

λ=−3 with multiplicity of 2

Matrix Adjoint Examples

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1	−4
4	−7

) or choose below

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

3	1	1
1	3	−1
2	4	1

Matrix Adjoint Calculator

Solution

Solution steps

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