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人気のある >

(2cos(x)-1)*(2sin(x)+1)=3-4sin^2(x)

解

(2 cos (x) - 1) \cdot (2 sin (x) + 1) = 3 - 4 sin^{2} (x)

解

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = \frac{π}{4} + πn

+1

度

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n, x = 4 5^{\circ} + 18 0^{\circ} n

解答ステップ

(2 cos (x) - 1) (2 sin (x) + 1) = 3 - 4 sin^{2} (x)

両辺から

3 - 4 sin^{2} (x)

を引く

4 sin^{2} (x) + 4 cos (x) sin (x) + 2 cos (x) - 2 sin (x) - 4 = 0

三角関数の公式を使用して書き換える

- 4 + 2 cos (x) - 2 sin (x) + 4 sin^{2} (x) + 4 cos (x) sin (x)

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= - 4 + 2 cos (x) - 2 sin (x) + 4 (1 - cos^{2} (x)) + 4 cos (x) sin (x)

簡素化

- 4 + 2 cos (x) - 2 sin (x) + 4 (1 - cos^{2} (x)) + 4 cos (x) sin (x) : 2 cos (x) + 4 cos (x) sin (x) - 4 cos^{2} (x) - 2 sin (x)

- 4 + 2 cos (x) - 2 sin (x) + 4 (1 - cos^{2} (x)) + 4 cos (x) sin (x)

拡張

4 (1 - cos^{2} (x)) : 4 - 4 cos^{2} (x)

4 (1 - cos^{2} (x))

分配法則を適用する:

a (b - c) = ab - a c

a = 4, b = 1, c = cos^{2} (x)

= 4 \cdot 1 - 4 cos^{2} (x)

数を乗じる:

4 \cdot 1 = 4

= 4 - 4 cos^{2} (x)

= - 4 + 2 cos (x) - 2 sin (x) + 4 - 4 cos^{2} (x) + 4 cos (x) sin (x)

簡素化

- 4 + 2 cos (x) - 2 sin (x) + 4 - 4 cos^{2} (x) + 4 cos (x) sin (x) : 2 cos (x) + 4 cos (x) sin (x) - 4 cos^{2} (x) - 2 sin (x)

- 4 + 2 cos (x) - 2 sin (x) + 4 - 4 cos^{2} (x) + 4 cos (x) sin (x)

条件のようなグループ

= 2 cos (x) - 2 sin (x) - 4 cos^{2} (x) + 4 cos (x) sin (x) - 4 + 4

- 4 + 4 = 0

= 2 cos (x) + 4 cos (x) sin (x) - 4 cos^{2} (x) - 2 sin (x)

= 2 cos (x) + 4 cos (x) sin (x) - 4 cos^{2} (x) - 2 sin (x)

= 2 cos (x) + 4 cos (x) sin (x) - 4 cos^{2} (x) - 2 sin (x)

2 cos (x) - 2 sin (x) - 4 cos^{2} (x) + 4 cos (x) sin (x) = 0

因数

2 cos (x) - 2 sin (x) - 4 cos^{2} (x) + 4 cos (x) sin (x) : - 2 (2 cos (x) - 1) (cos (x) - sin (x))

2 cos (x) - 2 sin (x) - 4 cos^{2} (x) + 4 cos (x) sin (x)

4

を書き換え

2 \cdot 2

- 4

を書き換え

2 \cdot 2

= 2 cos (x) - 2 sin (x) - 2 \cdot 2 cos^{2} (x) + 2 \cdot 2 sin (x) cos (x)

共通項をくくり出す

2

= 2 (cos (x) - sin (x) - 2 cos^{2} (x) + 2 sin (x) cos (x))

因数

cos (x) - sin (x) - 2 cos^{2} (x) + 2 sin (x) cos (x) : (1 - 2 cos (x)) (cos (x) - sin (x))

cos (x) - sin (x) - 2 cos^{2} (x) + 2 sin (x) cos (x)

因数

cos (x) - 2 cos^{2} (x) : cos (x) (1 - 2 cos (x))

cos (x) - 2 cos^{2} (x)

指数の規則を適用する:

a^{b + c} = a^{b} a^{c}

cos^{2} (x) = cos (x) cos (x)

= cos (x) - 2 cos (x) cos (x)

共通項をくくり出す

cos (x)

= cos (x) (1 - 2 cos (x))

因数

- sin (x) + 2 sin (x) cos (x) : sin (x) (- 1 + 2 cos (x))

- sin (x) + 2 sin (x) cos (x)

共通項をくくり出す

sin (x)

= sin (x) (- 1 + 2 cos (x))

= cos (x) (1 - 2 cos (x)) + sin (x) (- 1 + 2 cos (x))

書き換え

= (1 - 2 cos (x)) cos (x) - (1 - 2 cos (x)) sin (x)

共通項をくくり出す

(1 - 2 cos (x))

= (1 - 2 cos (x)) (cos (x) - sin (x))

= 2 (- 2 cos (x) + 1) (cos (x) - sin (x))

因数

1 - 2 cos (x) : - (2 cos (x) - 1)

1 - 2 cos (x)

共通項をくくり出す

- 1

= - (2 cos (x) - 1)

= - 2 (2 cos (x) - 1) (cos (x) - sin (x))

- 2 (2 cos (x) - 1) (cos (x) - sin (x)) = 0

各部分を別個に解く

2 cos (x) - 1 = 0 or cos (x) - sin (x) = 0

2 cos (x) - 1 = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

2 cos (x) - 1 = 0

1

を右側に移動します

2 cos (x) - 1 = 0

両辺に

1

を足す

2 cos (x) - 1 + 1 = 0 + 1

簡素化

2 cos (x) = 1

2 cos (x) = 1

以下で両辺を割る

2

2 cos (x) = 1

以下で両辺を割る

2

\frac{2 cos ( x )}{2} = \frac{1}{2}

簡素化

cos (x) = \frac{1}{2}

cos (x) = \frac{1}{2}

以下の一般解

cos (x) = \frac{1}{2}

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

cos (x) - sin (x) = 0 : x = \frac{π}{4} + πn

cos (x) - sin (x) = 0

三角関数の公式を使用して書き換える

cos (x) - sin (x) = 0

cos (x), cos (x) \neq = 0

で両辺を割る

\frac{cos ( x ) - sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

簡素化

1 - \frac{sin ( x )}{cos ( x )} = 0

基本的な三角関数の公式を使用する:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 - tan (x) = 0

1 - tan (x) = 0

1

を右側に移動します

1 - tan (x) = 0

両辺から

1

を引く

1 - tan (x) - 1 = 0 - 1

簡素化

- tan (x) = - 1

- tan (x) = - 1

以下で両辺を割る

- 1

- tan (x) = - 1

以下で両辺を割る

- 1

\frac{- tan ( x )}{- 1} = \frac{- 1}{- 1}

簡素化

tan (x) = 1

tan (x) = 1

以下の一般解

tan (x) = 1

tan (x)

πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

すべての解を組み合わせる

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = \frac{π}{4} + πn

人気の例

r=(2a)/((1+cos(x)))

r = \frac{2 a}{( 1 + cos ( x ) )}

cos^3(x)+cos^2(x)+cos(x)+1=0

cos^{3} (x) + cos^{2} (x) + cos (x) + 1 = 0

(cos^4(x))/3 =sin^2(x)

\frac{cos ^{4} ( x )}{3} = sin^{2} (x)

sin^3(x)cos(x)-sin^2(x)=0

sin^{3} (x) cos (x) - sin^{2} (x) = 0

sin^2(x)+sin^4(x)=0

sin^{2} (x) + sin^{4} (x) = 0