What is the general solution for tan(x)sin(x)+tan(x)=0 ?

The general solution for tan(x)sin(x)+tan(x)=0 is x=pin

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tan(x)sin(x)+tan(x)=0

tan (x) sin (x) + tan (x) = 0

x = πn

Degrees

x = 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (x) sin (x) + tan (x) = 0

Factor

tan (x) sin (x) + tan (x) : tan (x) (sin (x) + 1)

tan (x) sin (x) + tan (x)

Factor out common term

tan (x)

= tan (x) (sin (x) + 1)

tan (x) (sin (x) + 1) = 0

Solving each part separately

tan (x) = 0 or sin (x) + 1 = 0

tan (x) = 0 : x = πn

tan (x) = 0

General solutions for

tan (x) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 0 + πn

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = 0 + πn

0 + πn = πn

x = πn

x = πn

sin (x) + 1 = 0 : x = \frac{3 π}{2} + 2 πn

sin (x) + 1 = 0

Move

1

to the right side

sin (x) + 1 = 0

Subtract

1

from both sides

sin (x) + 1 - 1 = 0 - 1

Simplify

sin (x) = - 1

sin (x) = - 1

General solutions for

sin (x) = - 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{3 π}{2} + 2 πn

x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = πn, x = \frac{3 π}{2} + 2 πn

Since the equation is undefined for:

\frac{3 π}{2} + 2 πn

x = πn

y, tan (x y) = x

cot^{2} (x) - 3 csc (x) + 3 = 0

2 sin^{2} (\frac{θ}{2} - \frac{π}{6}) - 1 = 0

cos^{2} (3 6^{\circ}) - sin^{2} (3 6^{\circ}) = cos (x)

23 cos (x) = - 17 - cos (x)

What is the general solution for tan(x)sin(x)+tan(x)=0 ?
The general solution for tan(x)sin(x)+tan(x)=0 is x=pin