What is the general solution for solvefor y,tan(xy)=x ?

The general solution for solvefor y,tan(xy)=x is y=(arctan(x))/x+(pin)/x

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solvefor y,tan(xy)=x

solve for

y, tan (x y) = x

y = \frac{arctan ( x )}{x} + \frac{πn}{x}

Solution steps

tan (x y) = x

Apply trig inverse properties

tan (x y) = x

General solutions for

tan (x y) = x

tan (x) = a \Rightarrow x = arctan (a) + πn

x y = arctan (x) + πn

x y = arctan (x) + πn

Solve

x y = arctan (x) + πn : y = \frac{arctan ( x )}{x} + \frac{πn}{x}; x \neq = 0

x y = arctan (x) + πn

Divide both sides by

x; x \neq = 0

x y = arctan (x) + πn

Divide both sides by

x; x \neq = 0

\frac{x y}{x} = \frac{arctan ( x )}{x} + \frac{πn}{x}; x \neq = 0

Simplify

y = \frac{arctan ( x )}{x} + \frac{πn}{x}; x \neq = 0

y = \frac{arctan ( x )}{x} + \frac{πn}{x}; x \neq = 0

y = \frac{arctan ( x )}{x} + \frac{πn}{x}

cot^{2} (x) - 3 csc (x) + 3 = 0

2 sin^{2} (\frac{θ}{2} - \frac{π}{6}) - 1 = 0

cos^{2} (3 6^{\circ}) - sin^{2} (3 6^{\circ}) = cos (x)

23 cos (x) = - 17 - cos (x)

8 cos^{2} (θ) + 14 cos (θ) - 11 = 8 cos (θ) - 6

What is the general solution for solvefor y,tan(xy)=x ?
The general solution for solvefor y,tan(xy)=x is y=(arctan(x))/x+(pin)/x