What is the center ((x-5)^2)/(36)-(y^2)/(64)=1 ?

The center ((x-5)^2)/(36)-(y^2)/(64)=1 is (5,0)

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center ((x-5)^2)/(36)-(y^2)/(64)=1

center

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

(5, 0)

Solution steps

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 0), a = 6, b = 8

And the center is:

(5, 0)

y^{2} - \frac{x ^{2}}{9} = 1

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

9 x^{2} - 16 y^{2} - 54 x + 64 y - 127 = 0

What is the center ((x-5)^2)/(36)-(y^2)/(64)=1 ?
The center ((x-5)^2)/(36)-(y^2)/(64)=1 is (5,0)