What is the center (y^2)/(25)-(x^2)/(81)=1 ?

The center (y^2)/(25)-(x^2)/(81)=1 is (0,0)

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center (y^2)/(25)-(x^2)/(81)=1

center

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

(0, 0)

Solution steps

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 0 ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 9

And the center is:

(0, 0)

9 x^{2} - 16 y^{2} - 54 x + 64 y - 127 = 0

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

4 x^{2} - y^{2} = 16

x^{2} - \frac{y ^{2}}{9} = 1

What is the center (y^2)/(25)-(x^2)/(81)=1 ?
The center (y^2)/(25)-(x^2)/(81)=1 is (0,0)