What is the center y^2-(x^2)/9 =1 ?

The center y^2-(x^2)/9 =1 is (0,0)

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center y^2-(x^2)/9 =1

center

y^{2} - \frac{x ^{2}}{9} = 1

(0, 0)

Solution steps

y^{2} - \frac{x ^{2}}{9} = 1

Rewrite

y^{2} - \frac{x ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( x - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 3

And the center is:

(0, 0)

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

9 x^{2} - 16 y^{2} - 54 x + 64 y - 127 = 0

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1