What is the center 9x^2-16y^2-18x-64y-199=0 ?

The center 9x^2-16y^2-18x-64y-199=0 is (1,-2)

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center 9x^2-16y^2-18x-64y-199=0

center

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

(1, - 2)

Solution steps

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

Rewrite

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{4 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 4, b = 3

And the center is:

(1, - 2)

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

9 x^{2} - 16 y^{2} - 54 x + 64 y - 127 = 0

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

4 x^{2} - y^{2} = 16

What is the center 9x^2-16y^2-18x-64y-199=0 ?
The center 9x^2-16y^2-18x-64y-199=0 is (1,-2)