What is the center (x^2)/4-(y^2)/9 =1 ?

The center (x^2)/4-(y^2)/9 =1 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center (x^2)/4-(y^2)/9 =1

center

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 3

And the center is:

(0, 0)

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

y^{2} - \frac{x ^{2}}{9} = 1

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0