What is the circumference x^2+y^2-6x+6y-3=0 ?

The circumference x^2+y^2-6x+6y-3=0 is C=2sqrt(21)pi

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circumference x^2+y^2-6x+6y-3=0

circumference

x^{2} + y^{2} - 6 x + 6 y - 3 = 0

C = 221 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 6 x + 6 y - 3 = 0 : r = 21

C = 221 π

x^{2} + y^{2} \geq 4

x^{2} + y^{2} \leq 16

(x + 2)^{2} + (y - 2)^{2} = 13

x^{2} + y^{2} = 121

(x - 3)^{2} + (y + 2)^{2} = 10

What is the circumference x^2+y^2-6x+6y-3=0 ?
The circumference x^2+y^2-6x+6y-3=0 is C=2sqrt(21)pi