What is the circumference 2x^2+2y^2-4x+12y-12=0 ?

The circumference 2x^2+2y^2-4x+12y-12=0 is C=8pi

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circumference 2x^2+2y^2-4x+12y-12=0

circumference

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0 : r = 4

C = 2 π 4

Refine

C = 8 π

(x - 3)^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} - 20 x = 0

x^{2} + y^{2} + 2 x - 4 y = 76

x^{2} + y^{2} = 64

(x - 3)^{2} + (y - 4)^{2} = 4

What is the circumference 2x^2+2y^2-4x+12y-12=0 ?
The circumference 2x^2+2y^2-4x+12y-12=0 is C=8pi