What is the circumference (x-3)^2+(y-5)^2=25 ?

The circumference (x-3)^2+(y-5)^2=25 is C=10pi

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circumference (x-3)^2+(y-5)^2=25

circumference

(x - 3)^{2} + (y - 5)^{2} = 25

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 3)^{2} + (y - 5)^{2} = 25 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} - 20 x = 0

x^{2} + y^{2} + 2 x - 4 y = 76

x^{2} + y^{2} = 64

(x - 3)^{2} + (y - 4)^{2} = 4

x^{2} - 4 x + y^{2} + 2 = 0

What is the circumference (x-3)^2+(y-5)^2=25 ?
The circumference (x-3)^2+(y-5)^2=25 is C=10pi