en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2>= 4

Solution

circumference

x^{2} + y^{2} \geq 4

Solution

C = 4 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} \geq 4 : r = 2

C = 2 π 2

Refine

C = 4 π

Popular Examples

circumference x^2+y^2<= 16 circumference

x^{2} + y^{2} \leq 16

circumference (x+2)^2+(y-2)^2=13 circumference

(x + 2)^{2} + (y - 2)^{2} = 13

circumference x^2+y^2=121 circumference

x^{2} + y^{2} = 121

circumference (x-3)^2+(y+2)^2=10 circumference

(x - 3)^{2} + (y + 2)^{2} = 10

circumference (x-4)^2+(y-1)^2=4 circumference

(x - 4)^{2} + (y - 1)^{2} = 4

Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2>= 4 ?
The circumference x^2+y^2>= 4 is C=4pi